Kui kolmnurga ABC k]ljed jagada p osaks ning seej'rel [hendada kolmnurga tipud vastask[lje  sellise punktiga, 
mis jaotab vastask[lje suhtes 1/(p-1),  siis tekkiva kolmurga GHI ja kolmurga ABC pindalade suhe on  

Feynmani kolmurga [lesande [ldistus

\frac{S_{GHI}}{S_{ABC}}=\frac{{(p-2)}^{2}}{p^{2}-p+1}

\frac{S_{GHI}}{S_{ABC}}=\frac{{(4-2)}^{2}}{4^{2}-4+1}

n = 1 (slider from 1 to 5, step 1)
p = 6 (slider from 1 to 30, step 1)
A = (1.44, 3.18)
B = (-0.88, -1.72)
C = (6.92, -1.2)
t1, c, a, b = Polygon(A, B, C)
d = Circle(A, c / p)
e = Circle(B, a / p)
f = Circle(C, b / p)
D = Intersect(e, a, 1)
G = Intersect(d, c, 1)
H = Intersect(f, b, 1)
g = Segment(A, D)
h = Segment(G, C)
i = Segment(H, B)
E = Intersect(g, h)
F = Intersect(g, i)
I = Intersect(h, i)
t2, i_1, e_1, f_1 = Polygon(E, F, I)
Punktt2 = PointIn(t2)
Punktt1_{1} = PointIn(t1)
Punktt1 = PointIn(t1)
tekst5: "\frac{S_{GHI}}{S_{ABC}}=\frac{{(" + (LaTeX[p]) + "-2)}^{2}}{" + (LaTeX[p]) + "^{2}-" + (LaTeX[p]) + "+1}=\frac{" + (LaTeX[t2]) + "}{" + (LaTeX[t1]) + "}"